Question

To what temperature must a gas at 27 degrees ° C be cooled, so that its volume is reduced to 1/5 initial volume?​

Answer 1

Answer:

let's assume the final temperature is T2 K

T1 is (27+273) K = 300 K

let's say its primary volume is V1

and final volume V2 will be equal to V1 × (1÷5)

so, V1/T1= V2/T2

or, V1/300 =(V1× 0.2) /T2

or, T2= 0.2÷300

or, T2= 20÷ 30

or, T2= 2/3= 0.666

or, T2≈0.67 K=[0.67-273]°C= -272. 33°C