tomorrow I have test please solve this one no. 12
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principal money = 22,000
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
principal money = 22,000
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
principal money = 22,000
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
HOPE THIS WILL HELP YOU
PLEASE MARK AS BRAINLIEST
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
principal money = 22,000
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
principal money = 22,000
rate = 10%
We know formula for compound interest
Amount = Principal money [1 +r100] t
first find out the money after end of 2011 , So time = 1 years
Amount = 22,000 [1 +10100] 1
Amount = 22,000 (1110)
Amount = 24,200
Now let's say amount he saved in 2011 and deposit at end of year = x
So money at bank at beginning of 2012 = 24,200 + x
And we know at the end of 2012 he has Rs 39,820, So
⇒ 39,820 = (24,200 + x ) [1 +10100] 1
⇒ 39.820 = 24,200(1110) + x (1110)
⇒ 39.820 = 26,620 + x (1110)
⇒ 13,200 = x (1110)
⇒ x = 13,200011
⇒ x = 12000
So he saved Rs 12,000 in the end of 2011
HOPE THIS WILL HELP YOU
PLEASE MARK AS BRAINLIEST
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