Tomorrow is my exam... help...
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Horizontal component of the bullet : 500 km/hr
Vertical component = 1000 kmph
Resultant velocity of the bullet: √[500² + 1000²] = 500 √5 kmph
Angle made by the velocity of the bullet with vertical = Ф
TanФ = 500/1000 = 1/2
Angle = Ф = Tan⁻¹ 1/2 = 26.56°
Hope helps......
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