Tomorrow is my exam...
Please help!!!!
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rani712005:
The question is aa in the photo
As
u can multiply throughout the equation with any power.....in this question u had to eliminate 3 as the denominator
hence took a whole power of 3 throughout the equation
a,b,c are variables
so u cant take any values for a ,b and c
hence u have to eliminate that denominator to obtain the equation a+b+c
Please help yaar
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'Fraid that's not right. This is using x^3+y^3+z^3 = (x+y+z)^3... which is NOT true! To help see that the conclusion is wrong, put a = -1, b = -8, c = 27. Then a^(1/3) + b^(1/3) + c^(1/3) = -1 -2+3 = 0, as required, but a+b+c=18... not 0 !!
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