Question

Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.

Note:
- Need Full Explanation
- Don't Spam
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let the octagon be ABCDEFGH

Side of a regular octagon=5cm

area of octagon=area of rectangle HCDG+Area of trapezium Abch+area of trapezium GDEF

area of trapezium ABCH=\frac{1}{2}\times\left(sum\ of\ parallel\ sides\right)\left(dis\tan ce\right)=\left(area\ of\ trapezium\ GDEF\right)

2

1

×(sum of parallel sides)(distance)=(area of trapezium GDEF)

=\frac{1}{2}\times\left(11+5\right)\times4

2

1

×(11+5)×4

=32\ cm^232 cm

2

Area of reactangle HCDG=length\times breadthlength×breadth

=HC\times CD=HC×CD

=11\times5=11×5

=55\ cm^255 cm

2

Area of octagon=32\ cm^2+55cm^2+32cm^232 cm

2

+55cm

2

+32cm

2

=119cm^2119cm

2