Tossing of three coins find the probability of at least two heads?
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Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8. and, therefore, n(E5) = 4. Therefore, P(getting at least 2 heads) = P(E5) = n(E5)/n(S) = 4/8 = 1/2.
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Answer:
Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8. and, therefore, n(E5) = 4. Therefore, P(getting at least 2 heads) = P(E5) = n(E5)/n(S) = 4/8 = 1/2.
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