Question

Total mechanical energy E of an object of mass m, at a height h above the ground is given by the relation E = mgh +p^2/(2m) Find the dimensions of p. (g = acceleration due to gravity).

Answer 1

Explanation:

$dim \: of \: {p}^{2} \div 2m \: = dim \: of \: e \: = \: m {l}^{2} \sqrt{t } \\ p = m {l }^{ } {t}^{ - 1}$