Question

total no. of atom present in 34 g of NH3 is​

Answer 1

Answer:

In NH3 molecule one nitrogen atom and three hydrogen atoms are present. So in 1 mol of NH3 molecule, the total number of atoms present is 4. Thus, the number of atoms present in 34 grams of NH3 is 48×1023.

Answer 2

Given

34 g of NH₃

To Find

Total number of atoms present in 34 g of NH₃

Solution

We know that

Finding number of moles

$\sf \longrightarrow n=\dfrac{m}{M}$

Here

• n = Number of moles
• m = Given mass of compound
• M = Molar mass of compound

Given that

34 g of NH₃

Mass of NH₃ = 14 + 3 × 1 = 17 g

Hence

• m = 34 g
• M = 17 g

Substituting the values

We get

$\sf \longrightarrow n=\dfrac{34}{17} \ moles$

Therefore

$\sf \longrightarrow n=2 \ moles$

We know that

1 mole = 6.02 × 10²³ atoms

Hence

2 moles = 2 × 6.02 × 10²³ atoms

Therefore

2 moles = 12.04 × 10²³ atoms

Finding number of atoms

We know that

Number of atoms present in 1 molecule of NH₃ = 4 atoms

Hence

Number of atoms present in 34 g of NH₃

$\sf \longrightarrow 4 \times 12.04 \times 10^{23} \ atoms$

Therefore

$\sf \longrightarrow 48 \times 10^{23} \ atoms$

So

Number of atoms present in 34 g of NH₃ = 48 × 10²³ atoms