TOTAL NO. OF ATOMS REPRESENTED BY THE COMPOUND CuSo4.5H2O
NO. OF VALENCE ELECTRONS PRESENT IN 4.2g OF NITRIDE ION (N-) .........................
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1. 21 (5+4 O, 5×2 H, 1 Cu, 1 S)
2.
14 g N makes up to 1 mole
4.2 g N makes up to 4.2/14 = 0.3 mol
In 1 mole of N, there are 6.022E23 atoms
in each atom of N-, there are 6 valence electrons.
In 1 mole of N-, there are 6×6.022E23 valence electrons.
In 0.3 mole, there are (0.3×6×6.022E23)/1 valence electrons.
= 1.084E24
So, there are 1.084×10^24 valence electrons in 4.2 g of N- ion.
There are 5 electrons in the valence shell of N atom, but one electron is added as N- ion is formed. Thus making the number of valence electron 6 in N- ion.
2.
14 g N makes up to 1 mole
4.2 g N makes up to 4.2/14 = 0.3 mol
In 1 mole of N, there are 6.022E23 atoms
in each atom of N-, there are 6 valence electrons.
In 1 mole of N-, there are 6×6.022E23 valence electrons.
In 0.3 mole, there are (0.3×6×6.022E23)/1 valence electrons.
= 1.084E24
So, there are 1.084×10^24 valence electrons in 4.2 g of N- ion.
There are 5 electrons in the valence shell of N atom, but one electron is added as N- ion is formed. Thus making the number of valence electron 6 in N- ion.
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