Question

Total no of chloride ion in 222g of anhydrous calcium chloride is

Answer 1

Answer:

Similarly there are 2Cl- in one unit of CaCl2 hence there are( 1.205*10^24/2)=6.03*10^23 ions. The number of Ca2+ is 1.205*10^24ions while that of Cl- is 6.03*10^23ions present in 222g of CaCl2. Hence, there are 1.2044 X 1024 Ca2+ ions and 2.4088 X 1024 Cl- ions in 222 g of CaCl2

Answer 2

Explanation:

Total no. of chloride ions in 222 g of anhydrous calcium chloride will be there are 1.2044 X 1024 Ca2+ ions and 2.4088 X 1024 Cl- ions in 222 g of CaCl2.

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