CBSE BOARD XII, asked by smeenurmd2003, 11 months ago

Total number matches for knock out tournament is decided as​

Answers

Answered by nazhiyafarhana
8

Answer:

Explanation:

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In a knockout tournament, there is only one unbeaten team/ individual, i.e the eventual winner. Therefore, the rest of the participants have to loose in order to have one winner. Therefore, in a knockout tournament of 100 teams, there needs to be 99 games, each game eliminating one participant such that we are left with the winner after 99 games.

The games will have to organised in the following manner:

Round 1 - 28 players get a bye, i.e. straight entry to round 2 and 72 players play 36 matches in which 36 win and progress to the next round.

Round 2 - no of participants 64 (28 with direct entry to round 2 and 36 that won in round 1), no of matches 32

Round 3 - 32 participants play in 16 matches, 16 progress to next round

Round 4 - 16 participants play in 8 matches, 8 progress to next round

Round 5 - 8 participants play in 4 matches, 4 progress to next round

Round 6 - 4 participants play 2 matches, 2 progress to next round/ finals.

Finals - 2 participants play 1 match and the winner is determined.

Total number of matches - 36+32+16+8+4+2+1=99

The readon why 28 players get straight to round 2 is because we want to bring the no of participants in a round to 2^n form. If we had 50 matches between 100 participants, we would have 50 going through to next round and 25 matches between them in round 2 and 25 moving to round 3. Now we can have 12 matches between 24 participants and no opponent for the 25th participant. This is the reason we want to keep the no of participants to a 2^n form.

Answered by roopa2000
0

Answer:

Total number matches for knock out tournament is decided as​:

In a knockout tournament, there is only one unbeaten team/person, ie the eventual winner. Therefore, in order to be a winner, the rest of the participants have to lose. Therefore, in a knockout tournament of 100 teams, there should be 99 games, each game eliminating one participant in such a way that we are left with the winner after 99 games.

The Games will have to be organized in the following manner:

Round 1 - 28 players get a bye, i.e. direct entry into Round 2 and 72 players play 36 matches with 36 wins and progress to the next round.

Round 2 - Number of participants 64 (28 with direct entry in Round 2 and 36 who won in Round 1), number of matches 32

Round 3 - 32 participants play 16 matches, 16 progress to the next round

Round 4 - 16 participants play 8 matches, 8 advance to the next round

Round 5 - 8 participants play 4 matches, 4 progress to the next round

Round 6 - 4 participants play 2 matches, 2 progress to the next round/final.

Final - 2 participants play 1 match and the winner is determined.

Total number of matches - 36+32+16+8+4+2+1=99

Readon Why 28 players directly into round 2 is because we want to get the number of participants in round 2^n form. If we had 50 matches between 100 participants, we would have 50 matches in the next round and 25 between them and 25 in Round 2. Now we can have 12 matches between 24 participants and there is no opponent for the 25th participant. This is why we want to keep the number of participants in the form 2^n.

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