Math, asked by kkashu1486, 1 year ago

Total number of 9 digit numbers that are divisible by 5 is equal to

Answers

Answered by TanishqRaghuvanshi
1

total number of 9 digit number that are divisible by 5 is equal to 50

Answered by JeanaShupp
0

There are total 180,000,000 9-digit numbers that are divisible by 5.

Explanation:

The smallest 9-digit number that is divisible by 5 = 100,000,000 [In international system ]

The greatest 9 digit number that is divisible by 5 = 999,999,995

The Arithmetic progression for the given situation becomes :

100,000,000 , 100,000,005 , ............................., 999,999,995

Here , a= 100,000,000

d= 5

a(n) = 999,999,995

Formula for nth term:

a(n)=a+[n-1]d

Substitute all values , we get

999,999,995=100,000,000+[n-1]5

⇒[n-1]5= 999,999,995- 100,000,000= 899,999,995

Divide both sides by 5 , we get

n-1 = 179999999

⇒n= 179999999+1=180,000,000

Hence, there are total 180,000,000 9-digit numbers that are divisible by 5.

# Learn more :

The tens digit of a two digit number exceeds the units digit by5 . if the digite are reversed the new number is less by 45.if the sum of the digitbe 9.find the number

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