Question

total number of atoms are present in 34 gram of NH3

Answer 1

Answer : The total number of atoms present in 34 g of $NH_3$ are, $12.044\times 10^{23}$

Solution : Given,

Mass of $NH_3$ = 34 g

Molar mass of $NH_3$ = 17 g/mole

First we have to calculate the moles of $NH_3$

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}=\frac{34g}{17g/mole}=2mole$

Now we have to calculate the number of atoms present in $NH_3$

As, 1 mole contains $6.022\times 10^{23}$ number of atoms present in $NH_3$

So, 2 mole contains $2\times (6.022\times 10^{23})=12.044\times 10^{23}$ number of atoms present in $NH_3$

Therefore, the total number of atoms present in 34 g of $NH_3$ are, $12.044\times 10^{23}$