Question

total number of atoms present in 64 gram of a SO2

Answer 1

Hi friend
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Your answer
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Atomic mass of SO2 = [32 + (2 × 16)] u = 64 u

So,
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64 gm of SO2 = 1 mole

Therefore,
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Number of atoms in 64 gm of SO2 = 6.022 × 10²³


HOPE IT HELPS

Answer 2

Mass of SO2 = 32u + 2× 16u
= 64 u
Given mass = 64 g
Therfore
Given mass / Molar mass × Avagadros no = no of atoms present in it
64/ 64 × 6.02×20 ^23
= 6.02 × 10^23
Therefore correct ans is (a)

Hope it helps you