Question

Total number of electrons present in 34g OH are

Answer 1

Hydroxide :-

Symbol - OH

$\rule{200}{2}$

KEY POINTS TO REMEMBER :-

☸️ Oxygen :-

Atomic number = 8

Atomic mass = 16 atomic mass unit

Number of electrons = 8

Number of protons = 8

$\rule{200}{2}$

☸️ Hydrogen :-

Atomic number = 1

Atomic mass = 1 atomic mass unit

Number of protons = 1

Number of electrons = 1

$\rule{200}{2}$

Now,

Total mass of OH molecule = 16+1 =17 units

Total number of electrons present in OH molecule is :-

= 8 +1

=9 electrons

$\rule{200}{2}$

Given mass of OH = 34 g

Number of moles =

$= \frac{34}{17} \\ \\ \\2 \: moles$

$\rule{200}{2}$

Number of atoms in 2 moles OH molecule is as follows :-

$= 2 \times 6.022 \times {10}^{23} \: atoms$

$\rule{200}{2}$

Total number of electrons present is as follows :-

$= 9 \times 2 \times 6.022 \times {10}^{23} \\ \\ \\ = 9 \times 12.044 \times {10}^{23} \\ \\ \\ = 108.396 \times {10}^{23} \: electrons$

$\rule{200}{2}$