Question

total number of integral solutions for x*y*z=6! are?​

Answer 1

Answer:

Well, if x+y+z = 40 then (x-1) + (y-1) + (z-1) = 37.

Set a=(x-1), b=(y-1), and c=(z-1). Then a+b+c=37.

So the number of solutions to the first equation where x,y,z cannot be zero is the same as the number of solutions to the second equation were a,b,c can be zero.

Answer 2

Answer:

u see in pic

Step-by-step explanation:

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