Question

total number of ions in 55.5 g of cacl2

Answer 1

Answer:

Molar mass CaCl2 = 111g/mol

5.55g CaCl2 = 5.55/111 = 0.05 mol CaCl2

1 mol CaCl2 contains 2 mol Cl atoms

0.05 mol CaCl2 contains 0.05*2 = 0.1 mol Cl atoms.

Explanation:

Answer 2

Answer:

The total number of ions present in $55.5g$ of $CaCl_{2}$ calculated are $9.033\times 10^{23}$ ions.

Explanation:

Given,

The mass of $CaCl_{2}$ = $55.5g$

The total number of ions present in $55.5g$ of $CaCl_{2}$ =?

As we know,

The molar mass of $CaCl_{2}$ = $111g/mol$

Therefore,

• The number of moles of $CaCl_{2}$ = $\frac{Given mass}{Molar mass}$ = $\frac{55.5}{111}$ = $0.5 mol$

Now, the number of ions present in one $CaCl_{2}$ molecule are;

• $CaCl_{2} \rightarrow Ca^{+2} + 2Cl^{-}$

Thus, there are $3$ ions present in one $CaCl_{2}$ molecule.

Now,

• $1 mole$ = $6.022\times 10^{23}$ molecules.

Thus,

• $0.5 moles$ = $0.5\times 6.022\times 10^{23}$ molecules = $3.011\times 10^{23}$ molecules

As calculated,

• $1$ $CaCl_{2}$ molecule = $3 ions$
• $3.011\times 10^{23}$ molecules = $3\times 3.011\times 10^{23}$ ions = $9.033\times 10^{23}$ ions.

Hence, the total number of ions present in $55.5g$ of $CaCl_{2}$ = $9.033\times 10^{23}$ ions.