Total number of Na+ at edge centers of the unit cell
of NaCl if Cl- has fcc arrangement is
(1) 4
(2) 3
(3) 2
(4) 1
...
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Answer:
(2)
Explanation:
there are 12 edge centers and contribution at each edge center is 1/4.
so 12×1/4= 3 Na+ will be present
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