Question

Total number of neutrons present in 4g of heavy water(d2o) is

Answer 1

Hello Dear ☺

● Molecular mass of D2O = 20gms.

● Number of electron in 1 molecule of D2O = 10
Therefore number of neutron
=20-10
=10
Thus number of neutron in 1 molecule of D2O is 20 .

● Number of moles of D2O = Mass/Molar Mass.
= 4/20 =0.2 mole.

● Now using the formula,
Number of molecules= number of moles × Avogadro's number

● Number of molecule = 0.2 × 6.022× 10^23 .
= 1.204 × 10^23 molecules.

Now , number of neutrons in 1.204 ×10^23 molecules =
= 10× 1.204 ×10^23
●☆ = 12.04 ×10^23 neutrons. ☆●

Hope it Helps.

Have a nice day.

Answer 2

Answer:

No of moles = 4/20=0.2

In one molecul = moles × Avogadro's no

=0.2×6×10^23

One molecule =10 neutrons

0.2×6×10^23 = x

X= 2×6×10^23