Question

total number of nodal planes of all orbitals with n=3 is xy . then x+y is​

Answer 1

Answer. Thus the total number of nodal planes in n=3 are 0+3+8 =11

Answer 2

xy=3

x/3=y

y/3=x

x+y=x/3+y/3

x+y=x+y/3

3x+y=x+y

3x+y-x-y

2x

when n=3

2x=3

x=3/2=1.5