Total number of oxygen atoms present in 300 gram of acetic acid?
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No of oxygen atoms in one molecule = 2 (in CH3COOH)
molar mass of acetic acid = 60 grams ( 12 + 3 + 16 + 16 + 1)
mass of the sample = 300 g (given)
number of moles of acetic acid = 300g/60g = 5 moles
No of molecules of the acid in 5 moles = 5 x Avogadro's no = 5 x 6.022x10^23
= 3.011 x 10^24
Thus number of oxygen atoms in the sample = 2 x 3.011 x 10^24 = 6.022x10^24 atoms
Therefore, there are 6.022 x 10^24 atoms of O in the sample (whew!)
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