Question

total number of spectral lines formed in hyrogen spectrum when the electrons in hydrogen atom de-excites from the 6th energy level

Answer 1

Answer:

15

Explanation:

Assuming the electron is de-exciting to 1st shell,

Total number of spectral lines = $\frac{n(n+1)}{2}$

where n = difference in shell number ( =6-1 =5, in this case)

Therefore total number of lines = $\frac{(5)(6)}{2} = 15$

Answer 2

Assuming the electron is de-exciting to 1st shell,

Total number of spectral lines =

$\frac{n(n + 1)}{2}$

where n = difference in shell number ( =6-1 =5, in this case)

Therefore total number of lines =

$\frac{(5)(6)}{2}$

=15