total number of sterioisomers of C6H6Cl6
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Number of meso isomers = 2 ( n − 1 ) / 2. Total number of optical isomers = 2 n − 1.
Two of the stereounits are also stereocenters. The cis/trans relationship around the alkene is strictly a stereounit. . This molecule fits our new formula perfectly: there are three stereounits and zero meso stereoisomers, thus there are 23=8 stereoisomers in total.
The maximum number of stereoisomers that a molecule can have is 2n , where n is the number of chiral centres. A molecule with three chiral centres will have 23=8 stereoisomers. For example, the aldopentoses all have three chiral carbons, and there are eight stereoisomers
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----------DEAR--YOUR--ANSWER----------
Number of meso isomers = 2 ( n − 1 ) / 2. Total number of optical isomers = 2 n − 1.
Two of the stereounits are also stereocenters. The cis/trans relationship around the alkene is strictly a stereounit. . This molecule fits our new formula perfectly: there are three stereounits and zero meso stereoisomers, thus there are 23=8 stereoisomers in total.
The maximum number of stereoisomers that a molecule can have is 2n , where n is the number of chiral centres. A molecule with three chiral centres will have 23=8 stereoisomers. For example, the aldopentoses all have three chiral carbons, and there are eight stereoisomers
:-) :-) -------
MARK----
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Explanation:
This molecule fits our new formula perfectly: there are three stereounits and zero meso stereoisomers, thus there are 23=8 stereoisomers in total.
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