Physics, asked by anshu2375, 11 months ago

Total resistance of the figure

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Answered by AgentAV

Hope it helps.....

Plz mark brainliest!!

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monalisaborah48: Write it in the way as explained above...do mention Wheatstone bridge

AgentAV: will that work?

AgentAV: cuz the examiers r given ncert to find the ans

monalisaborah48: She said it won't come as it's not in the syllabus but if it comes write it in the way she said cbse will provide mark if the question is wrong

AgentAV: ok

AgentAV: Tell this to the guy too who asked this question

monalisaborah48: I told him in the comments section of my answer

monalisaborah48: I don't think he's that much interested in the answer

AgentAV: it was our job to tell him...

AgentAV: now he's on his own

Answered by monalisaborah48

Have a look at the picture below:

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anshu2375: no

anshu2375: no. do

monalisaborah48: But srry I can't give my number over here...I hope u understand

anshu2375: I want to be a good boy who study like you all

monalisaborah48: By the way is my ans correct?

anshu2375: yeah

anshu2375: bawli londia

monalisaborah48: Means??

monalisaborah48: This answer is wrong..I asked my teacher..

monalisaborah48: She said that there's a concept called Wheatstone bridge,which is not there in the syllabus of class10 according to this, the figure I have marked...r1 and r2 are in series and r3and r4 are in series...so by applying that concept r1/r2=1 also r3/r4=1 therefore r7 becomes ineffective by Wheatstone bridge concept so now we need to add the r1 and r2 i.e 4 and r3 and r4 ie 8 then as they are in parallel just calculate the resistance in parallel and ans comes out to be 2.6

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Total resistance of the figure