total surface area of a box,when each dimension is tripled?
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If length =l,breadth = b, height = h
Rotal surface area = 2(lb+lh+bh)----(1)
If each dimension is tripled
New length = 3l, breadth = 3b, height = 3h
TSA = 2[3l*3b+3l*3h+3b*3h]
= 9*2(lb+lh+bh)
=9*(1)
Means 9times of first tsa
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