Question

Total vapour pressure of mixture of 1 mol
B(pg = 150 torr) and 2 mol A (p = 240 torr) is
200 torr. In this case
(1) there is positive deviation from Raoult's law
(2) there is negative deviation from Raoult's law
(3) there is no deviation from Raoult's law
(4) molecular masses of A and B are also requried​

Answer 1

Explanation:

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Considering the mixture to be ideal,

Ptotal=PA∘χA+PB∘χB=50+160=210torr

But the experimental pressure is 200 torr. So, the mixture shows a negative deviation from Raoult's law.