Question

Toughest question.....What is the Remainder obtained when 2007^3+7002^3 is divided by 99

Answer 1

Here is your answer mate:-

$( {2007}^{3} + {7002}^{3} ) \div 99 = 46228081455$

Therefore, the remainder will be zero.


Hope it will help you.

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Answer 2

2007^3,+ 7002^3

= (2007+7002)^3 - 3×2007×7002(2007+7002)

= 9009)^3 - 3×2007×7002× 9009

AS 9009 is divisible by 99

so it's 0