Question

toughest questions from vectors and projectile​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER

Explanation:

Question

Solution 

Solution Average velocity vector is given as

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdtt

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow given

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)j

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)jor

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)jorv=drdt=−asin(kt)i+bcos(kt)jv=drdt=−asin(kt)i+bcos(kt)j

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)jorv=drdt=−asin(kt)i+bcos(kt)jv=drdt=−asin(kt)i+bcos(kt)jNow we calculate Average velocity vector as

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)jorv=drdt=−asin(kt)i+bcos(kt)jv=drdt=−asin(kt)i+bcos(kt)jNow we calculate Average velocity vector as<v>=∫(−asin(kt)i+bcos(kt)j)dtt<v>=∫(−asin(kt)i+bcos(kt)j)dtt

Solution Average velocity vector is given as<v>=∫vdtt<v>=∫vdttNow givenr=acos(kt)i+bsin(kt)jr=acos(kt)i+bsin(kt)jorv=drdt=−asin(kt)i+bcos(kt)jv=drdt=−asin(kt)i+bcos(kt)jNow we calculate Average velocity vector as<v>=∫(−asin(kt)i+bcos(kt)j)dtt<v>=∫(−asin(kt)i+bcos(kt)j)dtt<v>=acos(kt)i+bsin(kt)j

PLZ MARK AS BRAINLIEST AND FOLLOW