Tow oxides of metal contain 27.6% & 30.0% of oxygen
respectively. If the formula of the first oxide is M3O4.
What is the formula of the second oxide?
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let the molecular mass of the metal be X.
[3X/(3X+64)]*100=72.4
X=56
therefore M:O ratio=70/56 :30/16=2:3
the formula of second oxide is M₂O₃
[3X/(3X+64)]*100=72.4
X=56
therefore M:O ratio=70/56 :30/16=2:3
the formula of second oxide is M₂O₃
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