Tow Poles stand on the ground, with their feet 24m apart. if these poles are respectively 12m and 19m in height, find the distance between their tops.
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Let AB and CD be the given poles such that
AB = 12m, CD = 19m and AC = 24m
Join BD.
From B, draw BM ⊥ CD
Then,
CM = AB = 12m, BM = AC = 24m and
MD = CD - CM = (19-12)m = 7m
Now,
∆BMD is right angled at M
BD² = BM² + MD²
= (24²+7²)m²
= (576+49)m²
= 625m²
= (25m)²
→ BD = 25m
Hence, the distance between the tops of the poles is 25m
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