Question

tow year ago my age was 4 1/2 times the age of my son is six years ago my age was twines the square of my son age is the is the present age of my son ​

Answer 1

Answer:

10 years.

Step-by-step explanation:

Let 2 years ago, son's age be x.

So my age(2 years ago) =4.5 x

So, 6 years ago,

My age=4.5x-4

Son's age=x-4

B/C,

4.5x-4=2((x-4)^2)

or, 4x^2–41x+72=0

Solving the quadratic, we get-

x=8 or x=2.5(not possible)

So my present age of=4.5x+2=38

My son's present age=x+2=10.(Ans)

Answer 2

Answer:

Hope it will help you

Step-by-step explanation:

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