TP and TQ are 2 tangents to a circle if angle pOQ=110°find angle PTQ
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10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠ POQ = 110°, then ∠ PTQ is equal to. (A) 60° (B) 70° ... Reason : Radius and tangent are perpendicular to each other. Thus ∠OPQ is a right angle.
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angle PTQ = 70
The tangent makes right angle at the point of contact
therefore angle OPT = 90 and angle OQT =90
Now ,
angleOPT+ angleOQT+ anglePOQ+anglePTQ =360°
90°+90°+110°+anglePTQ =360°
290°+ anglePTQ =360°
anglePTQ =360° - 290°
anglePTQ =70°
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