Question

TP and TQ are two tangents to a circle with centre o so that angle POQ=120 degree find angle OTP

Answer 1

here according to theorem u see the angles subtended at the center while two tangents are drawn from same point are equal....

hence angle pot = angle qot =60degree
now in triangle pto
angle pot is 60 degree and angle tpo is 90 degree since it is radius through pt of contact

hence angle pto = 180-(90+60). = 30 degree

ur answer is 30 degree

Answer 2

Answer:

I think it helps

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