Question

TR perpendicular to PS and PQ parallel to TR and PS parallel to QR . If QR is 8 cm PQ is 3 cm and SP is 12 cm find area pqrs

Answer 1

Answer:

Step-by-step explanation:

LPTR=90 DEGREE

Lpqr=90 degree(in a parallelogram opposite angles are equal)

area of triangle pqr=1/2*8*3=12cm square

in the parallelogram diagonal pr divides it into 2 congruent triangles,

therefore triangle ptr=12 cm square

area of parallelogram pqrt=24 cm square

area(trs)=TR=3 cm(opp sides are equal)

pt=8 cm,ts=4 cm

therefore area of triangle rts=1/2*4*3=6 cm square

hence area of pqrs=24+6=30 cm square