Traffic lights at three different road crossing change after 48 seconds, 72 seconds
and 108 seconds respectively. At what time will they change together again if they
change simultaneously at 7 A.M.?
Answers
Answered by
11
Answer:
2 P.M.
Step-by-step explanation:
The LCM of 48,72,108= 432
When it is divided by 60then the quotient is 7 and remainder is 12.
7A.M.+7=14=2P.M. and 12 sec
Answered by
0
If the traffic lights change simultaneously at 7 a.m, then they will change simultaneously again after the LCM of the duration i.e. 48 s, 72 s and 108 s.
LCM of these durations by prime factorisation
48 = 2 × 2 × 2 × 2 × 3 = 2⁴ × 3
72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3²
108 = 2 × 2 × 3 × 3 × 3 = 2² × 3³
LCM of 48, 72 and 108 is 2⁴ × 3³ = 432 seconds.
Hence, They will change after 432 seconds i.e. 7 minutes 12 seconds.
The traffic lights will change after:
7 am + 7 minutes 12 seconds
07 : 07 : 12 am
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