Train A 120m long is moving with 20m/s. Train B is moving with 30m/s in opposite direction. In what time train B will cross train A?
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Answer:
Given,
SA=120m
SB=130m
vA=20m/s
vB=30m/s
The velocity of approach, v=vA+vB
v=20+30=50m/s
The train A has to cover the distance, S=SA+SB
S=120+130=250m
Time, t=vS=50250
t=5sec
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