Question

Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train A heading towards station A, and train B heading towards station B. Train A reaches station A after 4 h. Train B reaches station B after 3 1/2 h. Station A and Station B are 562.5 mi apart. What is the rate of the trains? Enter your answer in the box.

Answer 1

v₁ = speed of train A = v

v₂ = speed of the train B = v

t₁ = time of travel for train A = 4 h

t₂ = time of travel for train B = 3.5 h

d₁ = distance traveled by train A

distance traveled by train A is given as

d₁ = v₁ t₁                              eq-1

d₂ = distance travelled by train B

distance traveled by train B is given as

d₂ = v₂ t₂                              eq-2

Given that :

Total distance between station A  and station B = 562.5 mi

d₁ + d₂ = 562.5

v₁ t₁ + v₂ t₂ = 562.5

v (4) + v (3.5) = 562.5

v = 562.5/(7.5)

v = 75 mph

Answer 2

Answer:

90

Step-by-step explanation:

I just took the test and the answer was 90.