Question

Train A traveled 173 miles in five hours. For Train B, y = 31.35x represents its rate of speed over the same five hours. Analyze the date to determine which train traveled at a faster rate and by what factor? (round to nearest tenth)

Answer 1

Answer:

The Train A runs faster than Train B , by 3.25 miles per hours difference .

Step-by-step explanation:

Given as :

The distance cover by Train A = D = 173 miles

The time taken to cover 173 miles = T = 5 hours

Let The speed of train A = S  miles per hour

∵ Speed = $\dfrac{\textrm Distance}{\textrm Time}$

i.e s = $\dfrac{d}{t}$

Or, s = $\dfrac{173}{5}$

So, The speed of Train A = S = 34.6  miles per hour

Again

The rate of speed of Train B , y = 31.35 x

The time period = t = 5 hours

Since the rate of speed given expression , y = 31.35 x

So, The speed of train B = s =31.35 miles per hours

So, The difference between speed of both train = Speed of Train A - Speed of Train B

i.e The difference between speed of both train = S - s

or, The difference between speed of both train = 34.6 mph - 31.35 mph

Or, The difference between speed of both train = 3.25 mph

Hence, The Train A runs faster than Train B , by 3.25 miles per hours difference . Answer