Question

train accelarates from 36 km/h to 56km/h in 10 secs find accelaration and distance travelled​

Answer 1

Answer:

2 meter per second square

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

Given

Initial Velocity = 36 km/h or 10 m/s

Final Velocity = 56 km/h or 15.55 m/s

Time = 10 Seconds

Solution

Accelaration = (Final Velocity - Initial Velocity)/Time

Accelaration = (15.55 m/s - 10 m/s)/10 Seconds

Accelaration = (5.55 m/s)/10 Seconds

Accelaration = 0.555 ms^-2

Distance

By the Third law of Equation

2as = v^2 - u^2

1.11s = 241.80 m/s - 100 m/s

1.11s = 141.80 m/s

s = (141.80 m/s)/1.11

s = 127.74 m

So the Distance travelled is 127.74 Metre and the Accelaration will be of 0.555 ms^-2