Train is moving with an initial velocity of 5m/S with an acceleration of 5m/S^2 and takes time 4 secs. find the distance travelled????
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Here, u = 5m/s
a = 5m/s^2
t = 4s
Using, s = ut + 1/2at^2
= 5*4 + 1/2*5*4^3
= 60m ans
a = 5m/s^2
t = 4s
Using, s = ut + 1/2at^2
= 5*4 + 1/2*5*4^3
= 60m ans
Answered by
0
hey friend here is your answer,,,,,,
u = 5m/s
a = 5m/s²
t = 4s
using,,,,,
S = u t + 1/2 a t²
= 5×4+1/2×5×4³
= 60m.....
please mark me as a brain list......
u = 5m/s
a = 5m/s²
t = 4s
using,,,,,
S = u t + 1/2 a t²
= 5×4+1/2×5×4³
= 60m.....
please mark me as a brain list......
Anonymous:
galti see onhe chala gaya
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