Question

Train moveing with velocity of 54kmh-1 is accelerated so that its velocity becomes 72kh-1 in 15sec find the acceleration and distance coverd by train.​

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

✮ Initial velocity = 54km/h

✮ Final velocity = 72km/h

✮ Time of journey = 15s

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

✻ We have to find acceleration and distance covered by train in the given interval of time.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

➠ Acceleration is defined as the rate of change of change of velocity.

Mathematically,

$\dag\:\:\boxed{\bf{\purple{a=\dfrac{v-u}{t}}}}$

❅ Conversion :

⟶ 54km/h = 54 × 5/18 = 15m/s

⟶ 72km/h = 72 × 5/18 = 20m/s

☃ Acceleration of train :

$:\implies\tt\:a=\dfrac{v-u}{t}$

$:\implies\tt\:a=\dfrac{20-15}{15}$

$:\implies\tt\:a=\dfrac{5}{15}$

$:\implies\boxed{\bf{\red{a=0.33\:ms^{-2}}}}$

☃ Distance covered by train :

$:\implies\tt\:v^2-u^2=2as$

$:\implies\tt\:(20)^2-(15)^2=2(0.33)s$

$:\implies\tt\:400-225=0.66s$

$:\implies\tt\:175=0.66s$

$:\implies\boxed{\bf{\gray{s=265.15\:m}}}$

Answer 2

★ QUESTION :

Train moveing with velocity of 54kmh-1 is accelerated so that its velocity becomes 72kh-1 in 15sec find the acceleration and distance coverd by train.

GIVEN :

• Initial velocity of the trian = 54 km/h
• Final velocity of the train = 72 km /h
• Time taken to complete the distance = 15s

TO FIND :

• The acceleration and distance covered by the train = ?

STEP -BY- STEP EXPLAINATION :

As we, know that :

⟹ acceleration = v - u / time

➠ 54 km/h = 54 × 5/18 = 15m/s

➠ 72 km/h = 72 × 5/18 = 20m/s

➠ Applying here the formula of acceleration, to find acceleration :

⟹ a = v - u / t

after substituting here the value, as per the given formula that has to be put / apply.

⟹ a = 20 - 15 / 15

⟹ a = 5 / 15

after reducing it, we will get here the acceleration as :

⟹ a = 0.33 ms^-2

Therefore, the acceleration of the the train = 0.33 ms^-2

➠ Applying here the formula of finding the distance covered by the train, to find distance covered :

⟹ v² - u² = 2as

After substituting the values, for as per the given formulas :

⟹ (20)² - (15)² = 2.(0.33) s

Here, we will right after removing the signs of square (²) as :

⟹ 400 - 225 = 0.66s

⟹ 175 = 0.66s

⟹ s = 265. 15 m

Hence, the distance covered by the train = 265.15 m