Question

train running at 8/11 of its own speed reached a place in 5(1/2) h. how much time could be saved if the train would have run at its own speed​

Answer 1

Step-by-step explanation:

New speed = 7/11th of the usual speed

Then, new time = 11/7 of the usual time

So, 11/7 of usual time = 22 hours

Usual time = (22*7)/11

= 154/11

= 14 hours

Usual time is 14 hours and the time taken at less speed is 22 hours.

Hence, Time can be saved if the train would run at its usual speed 

⇒ 22 - 14 = 8 hours.