train running at 8/11 of its own speed reached a place in 5(1/2) h. how much time could be saved if the train would have run at its own speed
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Step-by-step explanation:
New speed = 7/11th of the usual speed
Then, new time = 11/7 of the usual time
So, 11/7 of usual time = 22 hours
Usual time = (22*7)/11
= 154/11
= 14 hours
Usual time is 14 hours and the time taken at less speed is 22 hours.
Hence, Time can be saved if the train would run at its usual speed
⇒ 22 - 14 = 8 hours.
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