Question

train running with a speed of 48 kmph has to negotiate a curve of radius 400m. When the distance between the railsis 1m. The height by which outer rail is to be raised with Respeit to inner rail is ​

Answer 1

Answer:-

=> radius of curved path is r. width of path is b m. the outer edge is raised by h w.r.t inner edge so that  a car with speed v can pass safe over it. the value of h is

=> tanθ = v²/rg = h/b

=> h=v²b/rg

substituting the   values according to given question,

v=48km/h =(48x 1000)/60x60m/s

=> 40/3 m/s

=> b = 1m

=> r = 400m

=> g = 9.8m/s2

=> h = (40/3)²x1/400x9.8

=> 0.0045m

=> 4.54cm is approximately

equal to 4.5 cm

=> The height by which outer rail is to be raised with Respeit to inner rail is 4.54cm.

I hope it helps you....