Question

Train starting from rest attains a velocity of 70km/h in 10 minutes.Assuming that the acceleration is uniform, find the acceleration and the distance travelled by the train while it attained the velocity?

Answer 1

u = 0 
v = 70 km/h = 175/9 m/s
t = 10 min = 600 sec
v= u+at
⇒175/9 = 0 + 600a
⇒a = 0.032 m/s²

s = ut+(1/2) at²
   = 0 + (1/2)×0.032×(600)²
   = 5760 m
   = 5.76 km

Answer 2

1-To find acceleration 
We have given that,
Initial velocity = 0 
Final velocity= 70 km/h = 175/9 m/s
Time taken = 10 min = 600 sec
From first equation of motion
v= u+at
By implying values
⇒175/9 = 0 + 600a
⇒a = 0.032 m/s²
2-To find acceleration
We have given that,
Initial velocity = 0 
Final velocity= 70 km/h = 175/9 m/s
Time taken = 10 min = 600 sec
From second equation of motion
s = ut+(1/2) at²
By implying values
= 0 + (1/2)×0.032×(600)²
 = 5760 m
 = 5.76 km