train starting from rest attains a velocity of 90 km per hour in 3 minutes .assuming that the acceleration is uniform. find the acceleration
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u=0km/h
v=90km/h
a=v-u / t
=90-0 / 3/60= 90×60 /3=1800km/h^2
v=90km/h
a=v-u / t
=90-0 / 3/60= 90×60 /3=1800km/h^2
Delsion:
I think you need to convert km/hr to m/s because time is given in form of minutes
i have converted min into hour
okay
Answered by
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u= 0m/s ; v= 90 km/h ; t= 3 min
= 25 m/s. = 180 sec
Since the acceleration (a) is constant.
Therefore, a = v-u/ t
= 25-0/180
= 0.138 m/s^2
= 25 m/s. = 180 sec
Since the acceleration (a) is constant.
Therefore, a = v-u/ t
= 25-0/180
= 0.138 m/s^2
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