Question

Train travelling at 20 metre per second -1 slated at 0.5 metre per second square for 30 second how far will it travel in this time

Answer 1

Answer :

The distance travelled by train at that time is 825m

Given :

• A train is at the velocity of 20m/s
• It is slated at acceleration of 0.5m/s² for a time period of 30s

To Determine :

• How far it will travel in that period of time.

Formula to be used :

$\sf \bullet \: \: s = ut + \dfrac{1}{2}at^{2}$

where

→s is distance covered

→u is initial velocity and

→t is time taken

→a is acceleration

Solution :

Given ,

u = 20m/s

t = 30s

a = 0.5m/s²

From equations of motion we have :

$\sf \implies s = 20\times 30 + \dfrac{1}{2}\times0.5\times30^{2} \\\\ \sf \implies s = 600 +\dfrac{1}{2}\times 0.5\times30\times30 \\\\ \sf \implies s = 600 + 225 \\\\ \sf \implies s = 825m$

Answer 2

CORRECT QUESTION :-

Train travelling at 20 ms⁻¹ accelerates at 0.5 m/s² for 30 second. How far will it travel in this time?

Given :-

$\dashrightarrow$ Initial velocity(u) = 20 m/s

$\dashrightarrow$ Acceleration(a) = 0.5 m/s²

$\dashrightarrow$ Time(t) = 30 secs

To find :-

The distance travelled(s) by the train in 30 s.

Formula to be used :-

$\displaystyle{\sf{s=ut+\frac{1}{2} at^2}}$

Solution :-

Putting the known values in the above formula :-

$\displaystyle{\sf{\longrightarrow s=20(30)+\frac{1}{2} 0.5(30)^2}}\\\\\displaystyle{\sf{\longrightarrow s=600+0.25(900)}}\\\\\displaystyle{\sf{\longrightarrow s=600+225}}\\\\\displaystyle{\sf{\longrightarrow s=825\ m}}$

∴ So, the train 825 m in 30 secs.