Question

Train X having length 130 m and train Y having length 145 m moving in opposite direction. They enter into a tunnel which have length equal to the sum of length of both trains. Trains meet after 10 second of entering in the tunnel. What percent of train X is left out the tunnel when it meet train Y if they have there speed in the ratio of 5:6?

Answer 1

Step-by-step explanation:

Let the speeds of the faster train be x m/s and that of the slower train be y m/s.

When the two trains are moving in the same direction:

Relative speed =(x−y) m/s

∴

$\frac{130m + 145m}{x - y} = 10$

⇒

$\frac{275m}{x - y} = 10$

⇒ .... (i)

When the two trains are moving in opposite direction:

Relative speed =(x+y) m/s

∴

$\frac{130m + 145m}{x - y} = 10$

⇒

x+y

130m+110m

=3⇒x+y=80 .... (ii)

Adding eqn (i) and (ii), we get

2x=84

⇒ x=42 m/s

∴ putting value of x in (i), we get

y=38 m/s.