Question

Trains A and B start moving at the same time from stations X and Y, respectively towards
and 8 hours to reach Y and X, respectively. If the speed of B is 25% more than that of A, the
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Answer 1

Step-by-step explanation:

11. X and Y are partners in a firm. They admit Z for ath share in firm's profits. Z brings

1,00,000 for his share of capital. The value of total assets of the firm is 2,70,000

and outside liabilities are assessed at 50,000 on that date. Z's share in hidden

goodwill be

(a) 80,000 (b) * 60,000 (c) * 1,00,000 (d) 20,000

Ans. (d)

4

X

4,00,000

1

1,00,000

(Hint - Hidden goodwill is

1

- ( 2,70,000 - 50,000 + 1,00,000)

= 4,00,000 - 3,20,000 = 80,000

4

Z's share is

= 20,000

Answer 2

Answer:

  speed of A  = (1.25 x (speed of A)) / 8

Step-by-step explanation:

From the above question,

They have given :

Train A and B start moving at the same time from stations X and Y, respectively and it takes 8 hours for Train B to reach station Y and Train A to reach station X.

The speed of Train B is 25% more than that of Train A.

To find the speed of Train A, we can use the formula:

                    distance = speed x time.

If it takes 8 hours for Train B to travel from station Y to X, and the speed of Train B is 25% more than Train A, we can set up the following equation:

      distance = (speed of A) x 8 = (1.25 x (speed of A)) x 8

To find the speed of Train A, we can solve for it by dividing both sides of the equation by 8:

     speed of A = distance / 8

                         = (1.25 x (speed of A)) / 8

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