Question

Transformation of sums and product.

Answer 1

HELLO DEAR,



sin(A+C/2)=sin{A+(π/2-A/2-B/2)



=>sin(π/2+A/2-B/2)

=>cos(A/2-B/2)sinC/2


=>sin(π/2-A/2-B/2)=cos(A/2+B/2)



Since,


sin(A+C/2)=nsinC/2,



so cos(A/2-B/2)= ncos(A/2+B/2)
cosA/2cosB/2+sinA/2sinB/2



---- ----= n cosA/2 cosB/2 - n sinA/2 sinB/2---


--------(1+tanA/2) ( tanB/2) = n - n tanA/2 tanB/2
---------tanA/2 tanB/2=(n - 1) / (n + 1).-------+---


I HOPE ITS HELP YOU DEAR,
:-THANKS :-