India Languages, asked by anmol4158, 8 months ago

translate in Hindi यथा जननी सर्वेषां पूज्या मान्या च भवति तथैव-उर
जन्मभूमिरपि मातृवत् सर्वेषां पूज्या मान्या च
वर्तते। यथा जननी दुग्धादि-दानेन स्वसन्ततीः
पालयति तथैव जन्मभूमिः शस्यादिभिः जनान्
पालयति पुष्यति च। मानवः स्वजन्मभूमौ यत्सुखं
लमते स्वर्गेऽपि तत्सुखं दुर्लभम् अस्ति। भगवता
रामचन्द्रेण रावणस्य वधानन्तरं स्वर्गस्य अपेक्षा
जन्मभूमेः महत्वं प्रतिपादितम्। यथा च ​

Answers

Answered by runisheen
2

Explanation:

Was the mother of all worship

Birth motherhood

Turn. As Janani Dugdadi-Daneen Swantanti:

Palayati Tathaiva Janmabhoomi: Shasyadibhi: Birth

Palayati Pushyati Ch. Manav: Self-birth

Lamte Swargapi Tatsukham Rarem Asti. God

Ramachandran Ravanasya Vdhanantran heavenly expectation

Janmabhoomi: Significance As such

Answered by ashok8102294811
0

Answer:

Brainly.in

What is your question?

1

Secondary School Math 5 points

If alpha and beta are the zeroes of x2-x-4 find out the value of

1) 1/alpha + 1/beta - alpha beta

2) alpha/beta + beta/alpha +2 ( 1/alpha +1/beta) + 3*alpha*beta..

plzz its urgent......

Ask for details Follow Report by Arohi03 06.05.2018

Answers

THE BRAINLIEST ANSWER!

Sol : We have quadratic equation x² - x - 4.

Given α and ß are their zeroes.

We know that,

Sum of roots = - ( coefficient of x )/ coefficient of x²

α + ß = - ( - 1 ) / 1

α + ß = 1 / 1 = 1.

Now,

Product of roots = constant term / coefficient of x²

αß = ( - 4 ) / 1

αß = -4.

1. 1/α + 1/ß - αß

ß + α

= ------------- - αß

αß

By substituting the values of ( α + ß ) and ( αß ),

= ( 1 / -4 ) - ( - 4 )

= ( - 1 / 4 ) + 4

- 1 + 16

= ----------------

4

= 15 / 4.

2. α/ß + ß/α + 2 ( 1/α + 1/ß ) + 3αß

α² + ß² + 2ß + 2α

= --------------------------- + 3αß

αß

α² + ß² + 2 ( α+ß )

= ------------------------- + 3αß ----- eq.1

αß

Now ,we don't have the value of ( α² + ß² ), so let's find it ,

( α + ß )² = α² + ß² + 2 αß

By substituting the values of ( α + ß ) and αß in above equation,

( 1 )² = α² + ß² + 2 ( - 4 )

1 = α² + ß² - 8

α² + ß² = 1 + 8

α² + ß² = 9

Now by substituting the values of ( α² + ß² ) ,αß and ( α + ß ) in eq.1,

9 + 2 ( 1 )

= --------------- + 3 ( - 4 )

-4

9 + 2

= -------------- - 12

-4

- 11

= -------------- - 12

4

-11 - 48

= --------------

4

= -59/4.

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